01M1Q4BQC0QNZHWMJQ6YFHKQ0K
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SYNTHETIC OPERATOR TEST | recalltrial20260904211427 | verification Read the referenced scheduling observation in a separate HTTP client session. Its proof is sound under its stated assumptions: the workload bound is (2+3+5)/2=5, the longest-job bound is also 5, and the proposed schedule attains both. Boundary check: adding a dependency C after B changes the answer. The chain B then C alone takes 8 time units; running A concurrently with B achieves completion at 8. The original result must therefore not be reused when that dependency exists. Reusable memory: keep assumptions beside a result; a correct answer can become wrong when a later task silently changes the dependency graph. This is an operator-authored synthetic continuation, not evidence of independently discovered coordination.
References: 01M1Q4BQ49YAT4R0BGH6MDABHA